Design an experiment to determine if this suggestion is true or not. Problem Statement: A student suggests that there is a proportional relationship between the height from which a ball is dropped and its rebound height. (b) On our graph plot height final as a function of height. Title: Investigating the relationship between drop height and rebound height of a ball. If the slope < 1, then some energy was lost. If the slope 1 the bals bounces are elastic. The restitution coefficient is denoted as ‘ e ’ and is a unit less quantity, and its values range between 0 and 1. Review the video to measure initial and final heights. (1) describe how b) Graph the rebound height vs the drop height. What is the Coefficient of Restitution The ratio of final velocity to the initial velocity between two objects after their collision is known as the coefficient of restitution. Use the video camera to video the motion of the ball from initial drop to maximum height of the first bounce. We proceeded to drop each type of sports ball from each of the five heights and did three trials for each height. The reason is that air resistance will slow the ball down and cause it to lose kinetic energy. Drop the toy ball 10 times from various heights such that the initial height is always measurable using the meter stick. Method First, we taped a yardstick against a perpendicular wall, then marked off every foot from the bottom to the top with chalk (1 feet, 2 feet, and so on until 5 feet). ![]() ![]() One problem the linear relation between drop height and rebound height doesn't work if the height is too large. Again we see that an interior fill of 30 mitigates the rebound best from that drop height. Trials are dropped from 20 cm (compare to Fig. According to the USTA regulations ball is tested for bounce by dropping it from a height of 100 inches (2.54 m) onto a bounce between 53 and 58 inches (1.3462 - 1.4732 m) is acceptable Rebound trajectories vs time for trials of partially filled acrylic spheres with water: empty sphere, 30 filled sphere, 70 filled sphere, and 100 filled sphere. Some of the kinetic energy of the ball is lost during the collision with the floor and the ball will not return to the original height. So, the higher you drop the ball from, the more potential energy it has -> the more kinetic energy it has when it hits the floor -> the higher it bounces back up. Then the ball rebounds, although with a slightly lower velocity due to slight energy loss, and bounces back up losing its vertical kinetic energy back into potential energy. Then on each bounce it rebounds to a fraction p of the previous maximum height. When the ball hits the floor the ball is squeezed transferring the kinetic energy back into potential energy, like in a spring. It’s easy to see where this model comes from: Suppose that the ball is released from height h. As it falls the potential energy is transferred into kinetic energy. ![]() The higher the drop distance, the more potential energy the ball has. It's a matter of conversion of potential energy energy into kinetic energy and vice versa.
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